The use of large integer

2010-03-30  来源:本站原创  分类:CPP  人气:185 

Available recursive formula: f (2m + 1) = f (2m)
f (2m) = f (2m - 2) + f (m)
Initial conditions: f (0) = f (1) = 1

Easy to know: f (2m) = f (0) + f (1) + ... + f (m)

Requirements: write a C # or C + + program, for any input n (0 ≤ n <100 million), calculating f (n).

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